14d^2-11d-3=0

Solution for 14d^2-11d-3=0 equation:

14d^2-11d-3=0

a = 14; b = -11; c = -3;
Δ = b2-4ac
Δ = -112-4·14·(-3)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-17}{2*14}=\frac{-6}{28}
=-3/14
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+17}{2*14}=\frac{28}{28}
=1
$